Question: Index n dimensional array with (n-1) d array


Index n dimensional array with (n-1) d array

Answers 1
Added at 2017-09-07 20:09

What is the most elegant way to access an n dimensional array with an (n-1) dimensional array along a given dimension as in the dummy example

a = np.random.random_sample((3,4,4))
b = np.random.random_sample((3,4,4))
idx = np.argmax(a, axis=0)

How can I access now with idx a to get the maxima in a as if I had used a.max(axis=0)? or how to retrieve the values specified by idx in b?

I thought about using np.meshgrid but I think it is an overkill. Note that the dimension axis can be any usefull axis (0,1,2) and is not known in advance. Is there an elegant way to do this?

Answers to

Index n dimensional array with (n-1) d array

nr: #1 dodano: 2017-09-07 20:09

Make use of advanced-indexing -

m,n = a.shape[1:]
I,J = np.ogrid[:m,:n]
a_max_values = a[idx, I, J]
b_max_values = b[idx, I, J]

For the general case:

def argmax_to_max(arr, argmax, axis):
    """argmax_to_max(arr, arr.argmax(axis), axis) == arr.max(axis)"""
    new_shape = list(arr.shape)
    del new_shape[axis]

    grid = np.ogrid[tuple(map(slice, new_shape))]
    grid.insert(axis, argmax)

    return arr[tuple(grid)]

Quite a bit more awkward than such a natural operation should be, unfortunately.

For indexing a n dim array with a (n-1) dim array, we could simplify it a bit to give us the grid of indices for all axes, like so -

def all_idx(idx, axis):
    grid = np.ogrid[tuple(map(slice, idx.shape))]
    grid.insert(axis, idx)
    return tuple(grid)

Hence, use it to index into input arrays -

axis = 0
a_max_values = a[all_idx(idx, axis=axis)]
b_max_values = b[all_idx(idx, axis=axis)]
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